Question

Pranav picks a 3 digit number and subtract it from the same number after reversing the Order of its digits if the difference is divided by 9 find the number

Answer 1

Difference of any three digit number by its reversing number is always a exact product of 9. i.e divisible by 9.

Let 100x+10y+z be the number; its reverse is 100z+10y+x.

Difference of the number will be:

(100x+10y+z)−(10z+10yb+x) = (100−1)x + (10−10)y + (1−100)z

= 99x−99z = 99(x−z)

So the difference of any three digit number with its reverse number is divisible by 9. ( Also 11 and 99)

Answer 2

Answer:

(ALSO 11 and 99)

Step-by-step explanation:

let 100X 10y+z be the number; it's reverse is 100z+10y+X.

different of the number will be:

(100× 10 y+2) - ( 10z+ 10yb+X) = (100-1) × + (10-10) y + (1-100) z= 99X99z= 99(X-Z).

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