prathima is twice older than her sister in 5 years time, she will be 2 years older than her sister. find how old are they both now?
Answers
Answered by
7
Let Prathima's age be 2x.
So, sister's age=x.
After 5 years,
Prathima's age=2x+5
Sister's age= x+5
According to the question,
(2x+5)=(x+5)+2
x=2.
So, Prathima's age is 2 years and her sister's age is 1 year.
So, sister's age=x.
After 5 years,
Prathima's age=2x+5
Sister's age= x+5
According to the question,
(2x+5)=(x+5)+2
x=2.
So, Prathima's age is 2 years and her sister's age is 1 year.
Answered by
9
Heya !!!
Let the age of prathima's sister be X years.
Age of prathima = 2X years.
After 5 years age of her sister = ( X + 5 ) years
After 5 years age of prathima = ( 2X + 5 ) yrs.
According to question,
Age of prathima after 5 years = ( Age of prathima's sister + 2 ).
2X + 5 = X + 5 + 2
2X - X = 7 - 5
X = 2.
Present age of prathima's sister = X = 2 years.
and,
Present age of prathima = 2X = 2 × 2 = 4 years.
★ HOPE IT WILL HELP YOU ★
Let the age of prathima's sister be X years.
Age of prathima = 2X years.
After 5 years age of her sister = ( X + 5 ) years
After 5 years age of prathima = ( 2X + 5 ) yrs.
According to question,
Age of prathima after 5 years = ( Age of prathima's sister + 2 ).
2X + 5 = X + 5 + 2
2X - X = 7 - 5
X = 2.
Present age of prathima's sister = X = 2 years.
and,
Present age of prathima = 2X = 2 × 2 = 4 years.
★ HOPE IT WILL HELP YOU ★
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