Question

Present age of veena's mother is 4 times veena's age. 5 years hence her age will be 21 years more than veena's age. Find their present ages ?

Answer 1

$\textbf{\huge{ANSWER:}}$

Let the age of Veena be = x

Mother's age = 4x

After 5 years:

Veena = x + 5
Mother's age = 4x + 5

According to the question:

4x + 5 = x + 5 + 21

=》 4x - x = 21 + 5 - 5

=》 3x = 21

=》 x = $\frac{21}{3}$

=》 x = 7

Therefore,

$\textbf{Veena = 7 years}$

$\textbf{Mother = 4x = 28 years}$

Hope it Helps!! :)

Answer 2

Here's the answer

Let the present age of Veena be x

Present age of Veena's mother = x + 4

Now,

After 5 years,

Their age will be =>

Veena's age = x + 5

Her mother's age = 4x + 5

Now,

As per your question,
$\sf{4x + 5 = x + 5 + 21 }$

$\sf{4x = x + 5 + 21 - 5}$

$\sf{4x - x = 21 + 5 - 5}$

$\sf{3x = 21}$

$\sf{x = \frac{21}{3}}$

$\sf{x = 7}$

Thus,

Age of Veena is 7 years.

Her mother's age = 4x = 4 × 7 = 28 years.

Thus,

Final answer =>

Age of Veena is 7 years

Age of Veena's mother is 28 years.

Thanks!