Question

Price of two tables is equal to the price of five chairs. Arwin buys 4 tables and 4 chairs and paid Rs 4396. Find the cost of 3 tables and 2 chairs. ​

Answer 1

Answer:

Solution



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Given 2T=5C

Given 10T+10C=7000

10T+Since 2T=5C, 10T2T=5 then 10C10C will be equal to 4T

Now 10T+4T=7000

14T=7000

∴T=500

Since 2T=5C2T=5C

Then 1000=5C

C=200

C=2

Total Price of 22 Chairs (C) and 44 Tables (T) will be 

2×200+4×500=2400

Answer 2

Let

price of each table = x

price of each chair = $\rm \dfrac{2x}{5}$

According to question,

$\rm :\longmapsto 4x + 4\times\dfrac{2x}{5} = 4396$

$\rm :\longmapsto x + \dfrac{2x}{5} = 1099$

$\rm :\longmapsto \dfrac{7x}{5} = 1099$

$\rm :\longmapsto x = \dfrac{5}{7} \times 1099$

$\rm :\longmapsto x = 785$

Hence we can find the cost as

$\rm :\longmapsto Cost \ of \ 3 \ tables = 3x = 2355$

$\rm :\longmapsto Cost \ of \ 2 \ chairs = \dfrac{4x}{5} = 628$