Question

Prive that SinA cosA -sinA cos(90-A)cosA/sec(90-A)-cosAsin(90-A)sinA/cosec(90-A)=0

Answer 1

Sina.cosa-sina cos(90-a).cosa/sec(90-a)-cosa.sin(90-a).sina/coseca(90-a)
=sina.cosa- sina sina .cosa/coseca-cosa.cosa.sina/seca
=sina.cosa-sina.sina.cosa.sina-cosa.cosa.sina.cosa
=sina.cosa-sin^3a.cosa-cos^3a.sina
=sina.cosa(1-sin^2a-cos^2a)
=sina.cosa(1-(sin^2a+cos^2a ))
=Sina.cosa(1-1)
=sina.cosa(0)
=0

Answer 2

here is your answer
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