Question

Probability of at least one of event a and b is 0.6.If a nd b occurs simultaneously probability os 0.2.Fin p(a')+p(b')

Answer 1

p(AUB)=0.6,P (A intersection B)=0.2

P (AUB)=P (A)+P (B)-P (A intersection B)

0.6=P (A)+P (B)-0.2

0.6+0.2=P (A)+P (B)

P (A)+P (B)=0.8

P (A bar )+P (Bbar)=(1-p (A))+(1-p (B))

=2-(P(A)+P (B))

=2-(0.8)

=1.2 is the answer

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