Probability of getting at least one head when tossing two coins
Answers
Answered by
0
Answer:
3/4
Step-by-step explanation:
4 outcomes (H, H) (T, H) (H, T) (T, T)
3 are favourable to event i.e. the first three
so 3/4
Answered by
0
Answer:
1/4
Step-by-step explanation:
possible outcome = [H,H],[T,T],H,T],T,H] THEREFORE P[E] = 4
SO PROBABLITY OF GETTING 1 HEAD = 1/4
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