probability questions
Two questions answers plzz reply..
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chance of student A to solve it = 1/2
chance of student B to solve it = 1/4
chance of student C to solve it = 1/5
So chance of atleast one of them to solve it is sum of this chances
1/2 + 1/4 +1/5 =>
= 19/20
chance of student B to solve it = 1/4
chance of student C to solve it = 1/5
So chance of atleast one of them to solve it is sum of this chances
1/2 + 1/4 +1/5 =>
= 19/20
Bhanumaster:
Plz mark brainliest
Answered by
1
19/20
this is the answer
this is the answer
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