Question

Problem - 3.9: The speed of a train is reduced from
60 km/h, to 15 km/h, while it travels a distance of
450 m. If the retardation is uniform, find how much
further it will travel before coming to rest ?​

Answer 1

Answer:

Explanation:

v= 15km/hr = 15*5/18= 75/18 m/s

u=60 km/hr= 60*5/18= 300/18 m/s

v^2=u^2+2as ( Third equation of motion)

5625/324= 90000/324+900a

-84375/324=900a

a = -0.28 m/s