Problem Description
A Company has decided to give some gifts to all of its employees. For that, company has given some rank to each employee. Based on that rank, company has made certain rules to distribute the gifts.
The rules for distributing the gifts are:
Each employee must receive at least one gift.
Employees having higher ranking get a greater number of gifts than their neighbours.
What is the minimum number of gifts required by company?
Constraints
1 < T < 10
1 < N < 100000
1 < Rank < 10^9
Input
First line contains integer T, denoting the number of testcases.
For each testcases:
First line contains integer N, denoting number of employees.
Second line contains N space separated integers, denoting the rank of each employee.
Output
For each testcase print the number of minimum gifts required on new line.
Time Limit
1
Examples
Example 1
Input
2
5
1 2 1 5 2
2
1 2
Output
7
3
Explanation
For testcase 1, adhering to rules mentioned above,
Employee # 1 whose rank is 1 gets one gift
Employee # 2 whose rank is 2 gets two gifts
Employee # 3 whose rank is 1 gets one gift
Employee # 4 whose rank is 5 gets two gifts
Employee # 5 whose rank is 2 gets one gift
Therefore, total gifts required is 1 + 2 + 1 + 2 + 1 = 7
Similarly, for testcase 2, adhering to rules mentioned above,
Employee # 1 whose rank is 1 gets one gift
Employee # 2 whose rank is 2 gets two gifts
Therefore, total gifts required is 1 + 2 = 3
Answers
Answer:
import java.util.Scanner;
class minimumGifts
{
public static void main(String args[])
{
Scanner sc = new Scanner(System.in); //creating object for sccaner
byte T=sc.nextByte();
byte i=0,total,p,N,a,cu,pre;
while(i<T)
{
total=1;
p=1;
N=sc.nextByte();
pre=sc.nextByte();
for(a=1;a<N;a++)
{
cu=sc.nextByte();
if(cu>pre)
p++;
else
p=1;
total+=p;
pre=cu;
}
System.out.println(total);
i++;
}
}
}
Explanation:
Answer:
import java.util.Scanner;
class minimumGifts
{
public static void main(String args[])
{
Scanner sc = new Scanner(System.in); //creating object for sccaner
byte T=sc.nextByte();
byte i=0,total,p,N,a,cu,pre;
while(i<T)
{
total=1;
p=1;
N=sc.nextByte();
pre=sc.nextByte();
for(a=1;a<N;a++)
{
cu=sc.nextByte();
if(cu>pre)
p++;
else
p=1;
total+=p;
pre=cu;
}
System.out.println(total);
i++;
}
}