product of 3 consecutive gp terms is 2744. find out first term
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Answered by
3
well , your question is incomplete. here we have given only one clue. but there are two unknown terms. so, not possible to find first term as usual . but it's possible to find 2nd terms as you can see below description.
Let three consecutive terms in geometric progression is a/r , a , ar .
product of three consecutive terms = 2744
(a/r)(a)(ar) = 2744
a³ = 14 × 14 × 14 = 14³
taking cube root both sides,
a = 14
hence, 2nd term in gp is 14.
Let three consecutive terms in geometric progression is a/r , a , ar .
product of three consecutive terms = 2744
(a/r)(a)(ar) = 2744
a³ = 14 × 14 × 14 = 14³
taking cube root both sides,
a = 14
hence, 2nd term in gp is 14.
Answered by
4
Let 3 consecutive term of gp are a/r,a,ar
Where a is the first term of gp
And r is the common ratio of gp
So , given that
product of these term = 2744
(a/r)×a×(ar) = 2744
a^3 = 2744
So,
a = 14
If there is any confusion please leave a comment below.
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