Question

Product of two number is 15,120 and their hcf is 6 find the number of passible pairs

Answer 1

Answer:

Step-by-step explanation:

let the two nos. be 6x & 6y.

A/Q         6x X 6y = 15120

          xy = 420.

Co-primes with product 420 are (1, 420), (3, 140), (4, 105), (5, 88), (7, 60), (12, 35), (15, 28) and (20, 21).

Hence , no of such pairs is 8.

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