proof of AAA similarity
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If in two triangles, corresponding angles are equal, then their corresponding sides are in the same ratio(or propotion) and hence the two triangles are similar.
In triangle ABC and DEF
A=D, B=E, C=F
Cut DP=AB and DQ =AC and join PQ
triangle ABC is correspondent to tri DPQ
B=P=E and PQ// EF
DP/PE=DQ/QF
AB/DE=AC/DF
Similarly, AB/= BC/EF and AB/DE=BC/EF=AC/DF.
Hece proofed
In triangle ABC and DEF
A=D, B=E, C=F
Cut DP=AB and DQ =AC and join PQ
triangle ABC is correspondent to tri DPQ
B=P=E and PQ// EF
DP/PE=DQ/QF
AB/DE=AC/DF
Similarly, AB/= BC/EF and AB/DE=BC/EF=AC/DF.
Hece proofed
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