Question

The volume of l gram mole of oxygen gas is 224ooml at 76omm of hg pressure • calculate the temperature of the gas (given=R=o•o82L atm

Answer 1

Use PV=nRT.

By this formula you can find the unknown quantity of question.

Here the calculation is quite easy thats why i am not solving it.

But I have told you the basic concept l.

Hope it helps.

Answer 2

PV = nRT

T = PV/nR

now p = density * g * h
p = 13600 * 10 * 0.76 = 1.03 * 10^5 = 1 atm

volume 22.4 L

R = 0.082

T = (1 * 22.4)/(1 * 0.082)

= 273.15 K