proove that √2 is an irrational number
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Let assume underoot 2 as rational number:
Let a and b the two co primes
So putting value
Underoot 2 = a/b
^2 * b = a
Squaring both the sides
2b2 = a2
If a2 is equal to 2
Then a is also equal to 2
Let take another co prime name it as c
C = 2c2
2c = 4c
a = 2c
Hence
A is also equal to 2
And C is also equal to 2
We know that irrational numbers are only 1 co prime number but there is two or more than prime numbers.
So, ^2 is irrational number
Let a and b the two co primes
So putting value
Underoot 2 = a/b
^2 * b = a
Squaring both the sides
2b2 = a2
If a2 is equal to 2
Then a is also equal to 2
Let take another co prime name it as c
C = 2c2
2c = 4c
a = 2c
Hence
A is also equal to 2
And C is also equal to 2
We know that irrational numbers are only 1 co prime number but there is two or more than prime numbers.
So, ^2 is irrational number
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