Propene □(→┴HBr) A □(→┴(i) Mg/ether) B
In the above sequence of reactions, B is
(a) propane (b) butane
(c) propene (d) ethane
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Explanation:
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Propene + HBr --------> A ---------> B
Mg/ether
The complete reaction is :
CH₃CHCH₂ + HBr ---> CH₃CH(Br)CH₃ ---Mg----> CH₃CH(MgBr)CH₂
propene (2 Bromo propane ) dry ether
CH₃CH(MgBr)CH₂ ----------> CH₃CH₂CH₃
(H₂O) Propane
The propene on reacting with hydrogen bromide obeys Markov's rule and forms 2 bromopropane .This on reacting with Mg in presence of dry ether forms grignard reagent which further on hydrolysis forms propane .
So, the answer is : (a) propane
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