Question

HOCl reacts on 3-methyl-2-pentene, the main product will
be :


(a) CH₃ -CH = C - CHOH - CH₃
|
Cl


OH CH₃
| |
(b) CH₃ - CH - C - CH₂ - CH₃
|
Cl

Cl CH₃
| |
(b) CH₃ - CH - C - CH₂ - CH₃
|
OH

(d) None of these

Answer 1

I think ....b....

here is your answer...mate...

Answer 2

3methyl 2 pentene reacts with HCl to produce 3- chloro 3 methyl pentane.

Explanation:

This is an example of Marokonikov's rule, when strong acid HCl (Hydrochloric acid) reacts with the 3-methyl-2 pentene and produce 3 chloro-3 methyl pentane.

This reacrion require  2 steps-

• At first, 3 methyl-2 pentene reacts with HCl and generate tertiary carbocation intermediate.
• The chloride anion then attacks the tertiary carbocation intermediate that give the main product 3-chloro-3 methyl pentane.
• The molecular formula of 3-chloro-3methyl pentane is C₆H₁₃Cl