prove cos 20°/. sin 70° = 1
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· Given cos 20 / sin 70 degree + 2 cos theta/ sin(90-theta) = k/2= cos(90-70)/ sin ... cos(90-70)/sin 70 + 2 cos theta/cos theta = k/2 [sin(90-theta) = cos theta] ... 1
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Hêy Fríèñd
Here is the Solution..
cos 20°
= cos ( 90° - 70° )
= sin 70° (Trigonometry ratios of complementary angles)
Therefore
Hence Proved
.
I Hope This Will Help You
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