Math, asked by clarksro17, 10 months ago

Prove:
((cosecA-secA)/(cosecA+secA))(cotA-tanA)=secAcosecA-2

Answers

Answered by pavankumar777

0

LHS

((1/sinA-1/cosA)/(1/sinA+1/cosA))(cosA/sinA-sinA/cosA)

=((cosA-sinA)/cosA*sinA)/((cosA+sinA)/cosA*sinA)((cos^2A-sin^2A)/sinA*cosA)

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