prove it
I will mark as brainlist
no fake answers otherwise I will report it
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let A=(1,2,3) B=(4,5,6) and C=(7,8,9)
AU(BnC)=(1,2,3)
as BnC is a null set
(AUB)=( 1,2,3,4,5,6)
(AUC)=1,2,3,7,8,9)
(AUB)n(AUC)=(1,2,3)
HENCE AU(BnC)=(AUB)n(AUC)
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