prove it please please....... brainliest
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required answer by Venn diagram
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raminder1:
robin
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Heya User,
--> Define subsets --> s , k , s' , k , such that :->
--> s ∩ s' = ∅ ;
--> A = s + k;
--> B = s' + k;
=> A ∩ B = k || A - B = s - s' [ Note : s∩s' = ∅ => s - s' = s ]
Now, A = k + s = k ∪ ( A - B ) = ( A∩B ) ∪ ( A - B )
Also, A∪B = s + s' + k = ( s + k ) + s' = A ∪ ( B - A )
--> We're done... Note :-> A∪B = B ∪ ( A - B ) is also true..
--> Define subsets --> s , k , s' , k , such that :->
--> s ∩ s' = ∅ ;
--> A = s + k;
--> B = s' + k;
=> A ∩ B = k || A - B = s - s' [ Note : s∩s' = ∅ => s - s' = s ]
Now, A = k + s = k ∪ ( A - B ) = ( A∩B ) ∪ ( A - B )
Also, A∪B = s + s' + k = ( s + k ) + s' = A ∪ ( B - A )
--> We're done... Note :-> A∪B = B ∪ ( A - B ) is also true..
hey
i m not getting symbols u used
can you give answer directly without s and k
:p --> A Logical proof by just some diagram =_=
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