Prove Pythagorean Theorem Numerically.
Answers
Answered by
7
hHi ,
Let a , b , c are three sides of a right triangle
ABC , hypotenuse is c
where a = 3 , b = 4 , c = 5 units of the
a² = 9 ,
b² = 16 ,
c² = 25
c² = a² + b²
By Pythagorean theorem ,
In a right Triangle , the square of the
hypotenuse is equal to sum of the squares of
the other two sides.
I hope this helps you.
:)
Let a , b , c are three sides of a right triangle
ABC , hypotenuse is c
where a = 3 , b = 4 , c = 5 units of the
a² = 9 ,
b² = 16 ,
c² = 25
c² = a² + b²
By Pythagorean theorem ,
In a right Triangle , the square of the
hypotenuse is equal to sum of the squares of
the other two sides.
I hope this helps you.
:)
Answered by
6
Hey there!!!
The Pythagorean theorem (P.G.T.) states that the square of hypotenuse side is equal to the sum of squares of the base side and the perpendicular side, in a right angled triangle.
Suppose ABC is a right angled triangle at B.
AB is the perpendicular side, BC is the base and AC is the hypotenuse side of the triangle.
Now according to P.G.T. -->
The result should be,
(AB)² + (BC)² = (AC)²
Now, lets prove it numerically:
Let the sides AB = 3cm
BC = 4cm
And , AC = 5cm
Now, according to P.G.T. --->
(AB)² + (BC)² = (AC)²
Plug in the values:
(3)² + (4)² = (5)²
9 +16 = 25
25 = 25
L.H.S. = R.H.S.
Hence P.G.T. is proved..
HOPE IT HELPS!!!
The Pythagorean theorem (P.G.T.) states that the square of hypotenuse side is equal to the sum of squares of the base side and the perpendicular side, in a right angled triangle.
Suppose ABC is a right angled triangle at B.
AB is the perpendicular side, BC is the base and AC is the hypotenuse side of the triangle.
Now according to P.G.T. -->
The result should be,
(AB)² + (BC)² = (AC)²
Now, lets prove it numerically:
Let the sides AB = 3cm
BC = 4cm
And , AC = 5cm
Now, according to P.G.T. --->
(AB)² + (BC)² = (AC)²
Plug in the values:
(3)² + (4)² = (5)²
9 +16 = 25
25 = 25
L.H.S. = R.H.S.
Hence P.G.T. is proved..
HOPE IT HELPS!!!
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