prove SinA cosA (tanA+cotA)=1
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Answered by
20
sinAcosA((sinA/cosA)+(cosA/sinA))
=sinAcosA(sin²A+cos²A/sinAcosA)
=sin²A+cos²A
=1
=sinAcosA(sin²A+cos²A/sinAcosA)
=sin²A+cos²A
=1
Answered by
6
LHS=SinAcosA(sinA/cosA+cosA/sinA)
SinAcosA(sin2A+cos2A/sinAcosA)
Sin2A+cos2A
1
RHS=1
Therefore,LHS=RHS.
SinAcosA(sin2A+cos2A/sinAcosA)
Sin2A+cos2A
1
RHS=1
Therefore,LHS=RHS.
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