Math, asked by koushikmitra, 1 year ago

prove SinA cosA (tanA+cotA)=1

Answers

Answered by Bharadwaj981

20

sinAcosA((sinA/cosA)+(cosA/sinA))

=sinAcosA(sin²A+cos²A/sinAcosA)

=sin²A+cos²A

=1

Answered by Anonymous

6

LHS=SinAcosA(sinA/cosA+cosA/sinA)
SinAcosA(sin2A+cos2A/sinAcosA)
Sin2A+cos2A
1
RHS=1
Therefore,LHS=RHS.

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