Math, asked by aashishprasad65, 1 year ago

Prove :
tan^3A-1/tanA-1=sec^2A+tanA

Answers

Answered by aadi7571

1

(tan^3A - 1)/(tanA - 1)

(tanA - 1)(tan^2A + 1 + tanA)/(tanA - 1)

sec^2A + tanA

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