Question

prove (tan A×sin A)+cos A = sec A​

Answer 1

to prove:

(tanA×sinA)+ cosA = secA

(sinA / cosA × sinA)+ cosA = secA

sin^2A/cosA + cosA = secA

(sin^2A+ cos^2A)/cosA = secA

using identity: sin^2A + cos^2A = 1

1/cosA = secA

secA = secA

hence proved

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Answer 2

I hope you understood the problem clearly