Prove: ( tanA + secA -1)/( tanA- secA+1) = (1+sinA)/cosA
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Answered by
171
To prove:
( tanA + secA -1)/( tanA- secA+1) = (1+sinA)/cosA
Proof:
(tanA - secA) - (sec2A - tan2A)/tanA + 1 - secA
(tanA - secA) (1 - (secA - tanA))/tanA + 1 - secA
(tanA - secA) (1 - secA + tanA)/tanA + 1 - secA
sec A + tan A
1/cosA + sinA/cosA
1 + sinA/cosA
Hence, Proved.
Answered by
12
Answer:
(tanA - secA) - (sec2A - tan2A)/tanA + 1 - secA
(tanA - secA) (1 - (secA - tanA))/tanA + 1 - secA
(tanA - secA) (1 - secA + tanA)/tanA + 1 - secA
sec A + tan A
1/cosA + sinA/cosA
1 + sinA/cosA
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