prove that (1+2w)(1+2w^2)(1-w-w^2)=6
Answers
Answered by
0
Answer:
1
Step-by-step explanation:
(1−w+w
2
)
6
+(1−w
2
+w)
6
.
=(−ω−ω)
6
+(−ω
2
−ω
2
)
6
, since ω+ω
2
=−1
=2
6
ω
6
+2
6
ω
12
=2
6
+2
6
=64+64=128, since ω
multiple of 3
=1
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