prove that (-1,4) , (-3,-6) and (3,-2) are the vertices of an isosceles right triangle
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Let's assume the sides of ∆ as AB, BC and CA.
AB = √[(- 1 + 3)² + (4 + 6)²] = √104
BC = √[(3 + 3)² + (- 2 + 6)²] = √52
CA = √[(3 + 1)² + (- 2 - 4)²] = √52
Hence we get BC = CA = √52.
Since we know that triangle having two sides equal is called isosceles triangle.
Hence Proved
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