Question

prove that: 1+cot square theta divided by (1+sec theta) = cosec theta

Answer 1

given problem - there is some thing wrong. it is not true...

  If theta is 45 deg, then LHS:  2 / (1 +√2)  = 2 (√2 - 1)
           and RHS = √2

$\frac{1+Cot^2\theta}{1+Sec\ \theta}=\frac{cosec^2\theta}{(Cos\theta+1)/cos\theta}\\\\=\frac{cos\ \theta}{Sin^2\theta(1+Cos\ \theta)}\\\\=cosec\theta(sec\theta-1)Cos^2\theta/sin^2\theta$

Answer 2

Answer:

ans is in the image

pls mark brainliest