prove that (1+i)⁴×(1+1/i)⁴=16
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SOLUTION :
LHS= (1+i)⁴×(1+1/i)⁴
= [(1+i)²]²×[(1-i)²]² [Here, 1/i = i/i² = i/-1 = -i]
= (1-1+2i)²×(1+i²-2i)²
= 4(i)² × 4(i)²
= -4 × (-4)
= 16 = RHS
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