PROVE THAT: 1+tan2Atan A=sec2A
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LHS = 1 + tan2AtanA
= 1 + 2tanA/1 - tan²A ×tanA
= 1 - tan²A + 2tan²A / 1 - tan²A
= 1 + tan²A / 1 - tan²A
= sec2A
=RHS
= 1 + 2tanA/1 - tan²A ×tanA
= 1 - tan²A + 2tan²A / 1 - tan²A
= 1 + tan²A / 1 - tan²A
= sec2A
=RHS
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