PROVE THAT: 1+tan2Atan A=sec2A
Answers
Answered by
13
LHS = 1 + tan2AtanA
= 1 + 2tanA/1 - tan²A ×tanA
= 1 - tan²A + 2tan²A / 1 - tan²A
= 1 + tan²A / 1 - tan²A
= sec2A
=RHS
= 1 + 2tanA/1 - tan²A ×tanA
= 1 - tan²A + 2tan²A / 1 - tan²A
= 1 + tan²A / 1 - tan²A
= sec2A
=RHS
Similar questions
History,
8 months ago
Social Sciences,
8 months ago
Environmental Sciences,
8 months ago
English,
1 year ago
Music,
1 year ago
Math,
1 year ago
Physics,
1 year ago