Prove that 2/√7 is irrational
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is equal to 1unto 7 underroot
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let us suppose 2/√7 is rational
therefore we get ,
2/√7=p/Q where p and q are in the simplest form
now,
2/√7=p/q
√7=2q/p
as we know that p and q are integers so 2q/p is a rational number which is equal to √7 .
it contradicts the fact that √7 is an irrational number
it is due to our wrong supposition
thus,2/√7 is irrational
therefore we get ,
2/√7=p/Q where p and q are in the simplest form
now,
2/√7=p/q
√7=2q/p
as we know that p and q are integers so 2q/p is a rational number which is equal to √7 .
it contradicts the fact that √7 is an irrational number
it is due to our wrong supposition
thus,2/√7 is irrational
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