Prove that 2 k ( n , 0 ) ( n , k ) 2 k 1 ( n , 1 ) ( n 1 , k 1 ) + 2 k 2 ( n , 2 ) ( n 2 , k 2 ) ... . . + ( 1 ) k ( n , k ) ( n k , 0 ) = ( n , k ) .
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