prove that 2cosA cosB =cos(A+B)+cos(A-B)
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hope it helps u...........
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Answered by
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taking RHS => cos(A+B) + cos(A-B
=> cosAcosB - sinAsinB + cosAcosB + sinAsinB
=> cosAcosB + cosAcosB
=> 2cosAcosB
I hope it helps.
=> cosAcosB - sinAsinB + cosAcosB + sinAsinB
=> cosAcosB + cosAcosB
=> 2cosAcosB
I hope it helps.
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