prove that: (2n-1)²+5n=4n²+n+1
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(2n-1)² + 5n
= [ (2n)² - 2×2n×1 + 1² ] + 5n
= 4n² - 4n + 1 + 5n
= 4n² + 5n - 4n + 1
= 4n² + n + 1 (proved)
= [ (2n)² - 2×2n×1 + 1² ] + 5n
= 4n² - 4n + 1 + 5n
= 4n² + 5n - 4n + 1
= 4n² + n + 1 (proved)
JeremyMcI:
i really dont understand what you did
simplification
(a-b)^2 = a^2 - 2ab + b^2
Answered by
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(2n-1)²+5n
⇒ (2n)² - 2 (2n)(1) + 1² + 5n
⇒ 4n² - 4n + 1 + 5n
⇒ 4n² + n + 1
Hence proved
⇒ (2n)² - 2 (2n)(1) + 1² + 5n
⇒ 4n² - 4n + 1 + 5n
⇒ 4n² + n + 1
Hence proved
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