prove that 2root5+3 is irrational
Answers
Answer:
p,q are integers then (p²-7q²)/2q is a rational number. Then √10 is also a rational number. But this contradicts the fact that √10 is an irrational number. √2+√5 is an irrational number.
Step-by-step explanation:
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Step-by-step explanation:
Given: 3 + 2√5
To prove: 3 + 2√5 is an irrational number.
Proof:
Let us assume that 3 + 2√5 is a rational number.
So it can be written in the form a/b
3 + 2√5 = a/b
Here a and b are coprime numbers and b ≠ 0
Solving 3 + 2√5 = a/b we get,
=>2√5 = a/b – 3
=>2√5 = (a-3b)/b
=>√5 = (a-3b)/2b
This shows (a-3b)/2b is a rational number. But we know that But √5 is an irrational number.
so it contradictsour assumption.
Our assumption of 3 + 2√5 is a rational number is incorrect.
3 + 2√5 is an irrational number
Hence proved