Math, asked by himanshu2722, 10 days ago

Prove that (3-√7)² is an irrational number.​

Answers

Answered by ks9846612
1

Answer:

(3-√7)²

3² + (√7)² - 2×3×√7

9 + 7 - 6√7

16 - 6√7

6√7 is not breakable into simplest form so it is proved that this is an irrational number

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