Math, asked by patilaayu777, 9 months ago

prove that 3 +√7 is an inrational number

Answers

Answered by Anonymous
3

&lt;body bgcolor ="black"&gt;&lt;font color="green red"&gt;</p><p>_/=root&lt;br&gt;</p><p> We have to prove that 3+_/7 is irrational.&lt;br&gt;</p><p></p><p>Let us assume the opposite, that 3+_/7 is rational.&lt;br&gt;</p><p></p><p>Hence 3+_/7 can be written in the form ba where a and b are co-prime and b=0&lt;br&gt;</p><p></p><p>Hence 3+7=ba&lt;br&gt;</p><p></p><p>⇒_/7=ba−3&lt;br&gt;</p><p></p><p>⇒7=ba−3b&lt;br&gt;</p><p></p><p>where _/7 is irrational and ba−3b is rational.&lt;br&gt;</p><p></p><p>Since,rational= irrational.&lt;br&gt;</p><p></p><p>This is a contradiction.&lt;br&gt;</p><p></p><p>∴ Our assumption is incorrect.&lt;br&gt;</p><p></p><p>Hence 3+_/7 is irrational.&lt;br&gt;</p><p></p><p>Hence proved.

&lt;marquee behaviour ="scroll"direction ="right"&gt;&lt;font color="red"&gt;hope it helps you &lt;/marquee behaviour ="scroll"direction ="right"&gt;

&lt;marquee behaviour ="scroll"direction ="up"&gt;&lt;font color="orange"&gt;^^^^^^^^ &lt;/marquee behaviour ="scroll"direction ="up"&gt;

Similar questions