Math, asked by patilaayu777, 7 months ago

prove that 3 +√7 is an inrational number

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Answered by Anonymous

$<body bgcolor ="black">_/=root We have to prove that 3+_/7 is irrational. Let us assume the opposite, that 3+_/7 is rational. Hence 3+_/7 can be written in the form ba where a and b are co-prime and b=0 Hence 3+7=ba ⇒_/7=ba−3 ⇒7=ba−3b where _/7 is irrational and ba−3b is rational. Since,rational= irrational. This is a contradiction. ∴ Our assumption is incorrect. Hence 3+_/7 is irrational. Hence proved.$

$<marquee behaviour ="scroll"direction ="right">hope it helps you </marquee behaviour ="scroll"direction ="right">$

$<marquee behaviour ="scroll"direction ="up">^^^^^^^^ </marquee behaviour ="scroll"direction ="up">$

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prove that 3 +√7 is an inrational number