prove that 5-2√3 is an irrational no. ?
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Let 5-2root3 be a rational no.
So 5-2root 3 =a/b
Then sove it by taking 5 on a\b side and then in next step take LCM
Then simply u can say that it is irrational
Plz can u ask details next time i amhaving a server problem.
Hope it helps.. Am sorry for not answering by solving it fully
So 5-2root 3 =a/b
Then sove it by taking 5 on a\b side and then in next step take LCM
Then simply u can say that it is irrational
Plz can u ask details next time i amhaving a server problem.
Hope it helps.. Am sorry for not answering by solving it fully
Answered by
0
Answer:
Step-by-step explanation:
Let 5-2√3 be rational number
Then,5-2√3=a/b,where a and b are coprime integers and b is not = 0.
-2√3=a/b-5
√3=a/-2b -5
We know that √3 is an irrational number.
So,our assumption is incorrect.
Therefore,5-2√3 is an irrational number.
Hope it helps.......
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