Question

prove that 6(n+6)-(2n+3)is odd number for all n is equal to natural number

Answer 1

Answer:

as n is natural no.

put n =1

6(n + 6) - (2n +3)

= 6(1+6) -(2*1 +3)

= 6(7) - 5

=42 - 5

= 37, which is a odd number

now put n=2

6(n +6) - (2n +3)

= 6( 2+6) - (2*2 +3)

=6*8 - (4+3)

= 48 - 7

=41, which is also a odd number

so, 6(n+6) - (2n+3) is odd for all n is equal to natural number.

Answer 2

Answer:

Factor, in mathematics, a number or algebraic expression that divides another number or expression evenly—i.e., with no remainder. For example, 3 and 6 are factors of 12 because 12 ÷ 3 = 4 exactly and 12 ÷ 6 = 2 exactly.

Step-by-step explanation:

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