prove that anglles opposite to equal sides an isosceles triangle are equal in measurement
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Step-by-step explanation:
Angles opposite to the equal sides of an isosceles triangle are also equal. Proof: Consider an isosceles triangle ABC where AC = BC. We need to prove that the angles opposite to the sides for ex:AC and BC are equal, that is, ∠CAB = ∠CBA. We first draw a bisector of ∠ACB and name it as CD.
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