Question

Prove that: AQ= 1/2 x (Perimeter of ΔABC)​

Answer 1

Answer:

Given: A circle touching the side BC of ΔABC at P and AB, AC produced at Q and R respectively

. Proof: Lengths of tangents drawn from an external point to a circle are equal.

⇒ AQ = AR, BQ = BP, CP = CR

. ∴ AQ is the half of the perimeter of ΔABC.