Prove that cos20 cos40 cos60 cos80=1/16
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sin20.sin40.cos60.cos80 = (1/2)[2 sin20.sin40.cos60.cos80]
= (1/2){[cos 20 + cos 60]cos60.cos80}
= (1/2){[cos 20 + (1/2)](1/2).cos80}
= (1/8){[2cos 20 + 1].cos80}
= (1/8)[2cos 20 cos80 + cos80]
= (1/8)[cos 100 + cos60 + cos80]
= (1/8)[- cos 80 + (1/2) + cos80]
= (1/8) (1/2) = (1/16)
= RHS
= (1/2){[cos 20 + cos 60]cos60.cos80}
= (1/2){[cos 20 + (1/2)](1/2).cos80}
= (1/8){[2cos 20 + 1].cos80}
= (1/8)[2cos 20 cos80 + cos80]
= (1/8)[cos 100 + cos60 + cos80]
= (1/8)[- cos 80 + (1/2) + cos80]
= (1/8) (1/2) = (1/16)
= RHS
nidhanajmaranjith35:
Thanks
Answered by
3
DEAR STUDENT,
Kindly check the attached papers for a detailed solution along with step by step elaboration to reach our final solution that is our final desired or required answer to this query that is completely proved.
Which is the required proof or solution process for this type of query.
Hope this helps you and solves your doubts for applying trigonometric identifies to reach a proper solution or a proof!!!!!
Kindly check the attached papers for a detailed solution along with step by step elaboration to reach our final solution that is our final desired or required answer to this query that is completely proved.
Which is the required proof or solution process for this type of query.
Hope this helps you and solves your doubts for applying trigonometric identifies to reach a proper solution or a proof!!!!!
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