Math, asked by Anjalibinodhiya, 1 year ago

prove that: cos²A+tan²A-1/sin²A=tan²A

Answers

Answered by Sandeep03edu
5
((Cos ^{2} A +  tan^{2}A - 1 ) / Sin ^{2}A =\ \textgreater \      Cos ^{2}A/ Sin^{2}A + Tan ^{2}A/ Sin^{2}A  -1/Sin^{2}A    =\ \textgreater \  Cot^{2}A + Sec^[tex]=\ \textgreater \  1 + Sec^{2}A   =\ \textgreater \   Tan^{2}A  {2}A - Cosec^{2}A =\ \textgreater \ { Cot^{2}A - Cosec^{2}A } + Sec^{2}A [/tex]



Hence proved that
LHS = RHS

Answered by Amrinder007
13
put value of 1 = sin2 + cos2 and then solve the problem
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