prove that cube root of two is a irrational number
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A different approach is using polynomials and the rational root theorem. Since 3√2 is a root of f(x)=x3−2, it is enough to show that if f(x) has no rational roots, then 3√2 is irrational.
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A different approach is using polynomials and the rational root theorem. Since 3√2 is a root of f(x)=x3−2, it is enough to show that if f(x) has no rational roots, then 3√2 is irrational.
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