Math, asked by souryajitdutta93, 11 months ago

prove that cube root of two is a irrational number ​

Answers

Answered by Anonymous
4

A different approach is using polynomials and the rational root theorem. Since 3√2 is a root of f(x)=x3−2, it is enough to show that if f(x) has no rational roots, then 3√2 is irrational.

Answered by anayachaturvedi31120
0

Answer:

A different approach is using polynomials and the rational root theorem. Since 3√2 is a root of f(x)=x3−2, it is enough to show that if f(x) has no rational roots, then 3√2 is irrational.

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