prove that - H.C.F.(ka,kb)=k.H.C.F.(a,b)
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Step-by-step explanation:
For this, we need to find HCF of (ka,kb) & k*HCF of (a,b) separately.
HCF(ka,kb):
ka= k * a * 1
kb= k * b * 1
HCF= k ----------------------[1]
k*HCF(a,b):
a= 1*a
b= 1*b
As we can see a & b have no other common factor than 1, HCF= 1
k*HCF(a,b)= k * 1 = k ------------[2]
Thus, from [1] & [2],
HCF (ka,kb) = k * HCF (a,b)
Hope it help you.
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