Prove that if 2 triangles having the same base and equal areas lie between the same parallels
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Theorem: Triangles having the same base and equal areas lie between the same parallels.
Given: DPQR and DSQR such that ar (DPQR) = ar (DSQR).
Construction: Draw PL and SM perpendicular to QR.
To prove: PS || QR
Proof:-we know that,area of a triangle=
1/2 x base x height
therefore, ar(ΔPQR)=
1/2 x QR x PL and ar(ΔSQR) =1/2 x QR xSM
given that ar(ΔPQR) =
ar(ΔSQR)
1/2 x QR x PL=1/2 x QR x SM
==>PL=SM
hence, PS || QR
HOPE IT HELPS YOU IF HELPED PLZ FOLLOW ME........
Given: DPQR and DSQR such that ar (DPQR) = ar (DSQR).
Construction: Draw PL and SM perpendicular to QR.
To prove: PS || QR
Proof:-we know that,area of a triangle=
1/2 x base x height
therefore, ar(ΔPQR)=
1/2 x QR x PL and ar(ΔSQR) =1/2 x QR xSM
given that ar(ΔPQR) =
ar(ΔSQR)
1/2 x QR x PL=1/2 x QR x SM
==>PL=SM
hence, PS || QR
HOPE IT HELPS YOU IF HELPED PLZ FOLLOW ME........
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