Prove that if a number is tripled , then it's cube is 27 times the cube of the given number ?
Answers
Answer:
Let the given number be x,
then, triple of given number=3x
cube of triple of given number=(3x)^3=3^3 ×x^3=27 × x^3
now,
cube of given number=x^3
27 times of cube of given number=27 × x^3
hence,
cube of triple of given number=27 times of cube of given number(hence proved)
Answer:
Let the given number be x.
The cube of the given number = ( x )³ = x³
Now, the tripled number = 3 × x = 3x
Now, from given condition,
∴ ( 3x )³ = 27x³
Now, from second condition,
( 3x )³ = 27x³
Hence Proved!
Now, we will see if our proof is right or not.
Let assume that x = 2.
∴ From the first condition,
( 3 × 2 )³ = ( 6 )³ = 216 ...... ( 1 )
And now, from second condition,
27 × ( 2 )³ = 27 × 8 = 216 ........... ( 2 )
From equations ( 1 ) & ( 2 ), we can say that our proof is correct.
Hence,
If a number is tripled then its cube is 27 times the cube of the given number.
★ Some Interesting Facts ★
If we multiplied a number by another number and then we powered it ( index ) to that another number, we will get that power to the multiplied the given number.
Let's see here :
If we doubled a number then its square is 4 times the square of the given number.
Let the number be 3.
∴ From first condition,
∴ (2 × 3)² = ( 6 )² = 36 ...... ( 1 )
From second condition,
∴ 4 × ( 3 )² = 4 × 9 = 36 ....... ( 2 )
So, from ( 1 ) & ( 2 ), we can conclude the above fact.