Prove that , log 2 with base 10 > 0.3
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exponential form of log 2 base 10 : base(10) raised to log of number(x)=number(2)
therefore 10^x=2xlog10=log2
x=log2=.30103>0.3
therefore 10^x=2xlog10=log2
x=log2=.30103>0.3
sbis04:
how did you get .30103
Answered by
2
0.3 is rhe answer hope it's help you
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