prove that, log x base 1/y× log y base 1/z × log z base 1/x =-1
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Atulkrishnan:
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dear friends
here you proceed by the concept is
logx base 1/y
=logx base y^(-1)
= -logx base e/log y base e
in the same way you break all log
I.e logy base 1/z=-logy base e/logz base logz base 1/x=-logz base e/logx base e
now multiply all you gain -1
hence proved
here you proceed by the concept is
logx base 1/y
=logx base y^(-1)
= -logx base e/log y base e
in the same way you break all log
I.e logy base 1/z=-logy base e/logz base logz base 1/x=-logz base e/logx base e
now multiply all you gain -1
hence proved
I hope this is helpful
please mark as brainliest
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